mirror of
https://github.com/arnaucube/math.git
synced 2026-01-11 08:21:31 +01:00
complete Noetherian rings/modules notes, add Hilbert basis theorem, some Noetherian exercises (#2)
* add proof for split exact sequences * port exercise R.2.9 * Noetherian rings: add ex. 3.2 & 3.5 * Hilbert basis theorem, Noetherian module properties * add Noetherian exercises 3.3 & 3.4
This commit is contained in:
@@ -461,8 +461,12 @@
|
||||
\begin{enumerate}[i.]
|
||||
\item show that $\eta$ is a \emph{well defined} map:
|
||||
|
||||
if $g_1 K=g_2 K$, then for some $k \in K$, $g_1 k =g_2$, so
|
||||
$$\eta(g_1K)=\psi(g_1) = \psi(g_1)\psi(k) = \psi(g_1 k) = \psi(g_2) = \eta(g_2 k)$$
|
||||
if we have two representatives of the same coset, ie. $g_1 K=g_2 K$, we want to show that $\eta(g_1 K) = \eta(g_2 K)$, so that $\eta$ is a well-defined map.
|
||||
|
||||
\vspace{0.3cm}
|
||||
By the coset properties for some $k \in K$, $g_1=g_2 k$, so
|
||||
|
||||
$$\eta(g_1K)=\psi(g_1) = \psi(g_2 k) = \eta(g_2 k K) = \eta(g_2 K)$$
|
||||
|
||||
Thus, $\eta$ does not depend on the choice of coset representatives, and
|
||||
the map $\eta: G/ker(\psi) \longrightarrow \psi(G)$ is uniquely defined
|
||||
|
||||
Reference in New Issue
Block a user