grapevine-sonobe/circom/node_modules/circomlib/circuits/binsum.circom
circom/node_modules/circomlib/circuits/binsum.circomRaw
1/*
2 Copyright 2018 0KIMS association.
3
4 This file is part of circom (Zero Knowledge Circuit Compiler).
5
6 circom is a free software: you can redistribute it and/or modify it
7 under the terms of the GNU General Public License as published by
8 the Free Software Foundation, either version 3 of the License, or
9 (at your option) any later version.
10
11 circom is distributed in the hope that it will be useful, but WITHOUT
12 ANY WARRANTY; without even the implied warranty of MERCHANTABILITY
13 or FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public
14 License for more details.
15
16 You should have received a copy of the GNU General Public License
17 along with circom. If not, see <https://www.gnu.org/licenses/>.
18*/
19
20/*
21
22Binary Sum
23==========
24
25This component creates a binary sum componet of ops operands and n bits each operand.
26
27e is Number of carries: Depends on the number of operands in the input.
28
29Main Constraint:
30 in[0][0] * 2^0 + in[0][1] * 2^1 + ..... + in[0][n-1] * 2^(n-1) +
31 + in[1][0] * 2^0 + in[1][1] * 2^1 + ..... + in[1][n-1] * 2^(n-1) +
32 + ..
33 + in[ops-1][0] * 2^0 + in[ops-1][1] * 2^1 + ..... + in[ops-1][n-1] * 2^(n-1) +
34 ===
35 out[0] * 2^0 + out[1] * 2^1 + + out[n+e-1] *2(n+e-1)
36
37To waranty binary outputs:
38
39 out[0] * (out[0] - 1) === 0
40 out[1] * (out[0] - 1) === 0
41 .
42 .
43 .
44 out[n+e-1] * (out[n+e-1] - 1) == 0
45
46 */
47
48
49/*
50 This function calculates the number of extra bits in the output to do the full sum.
51 */
52 pragma circom 2.0.0;
53
54function nbits(a) {
55 var n = 1;
56 var r = 0;
57 while (n-1<a) {
58 r++;
59 n *= 2;
60 }
61 return r;
62}
63
64
65template BinSum(n, ops) {
66 var nout = nbits((2**n -1)*ops);
67 signal input in[ops][n];
68 signal output out[nout];
69
70 var lin = 0;
71 var lout = 0;
72
73 var k;
74 var j;
75
76 var e2;
77
78 e2 = 1;
79 for (k=0; k<n; k++) {
80 for (j=0; j<ops; j++) {
81 lin += in[j][k] * e2;
82 }
83 e2 = e2 + e2;
84 }
85
86 e2 = 1;
87 for (k=0; k<nout; k++) {
88 out[k] <-- (lin >> k) & 1;
89
90 // Ensure out is binary
91 out[k] * (out[k] - 1) === 0;
92
93 lout += out[k] * e2;
94
95 e2 = e2+e2;
96 }
97
98 // Ensure the sum;
99
100 lin === lout;
101}